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Consider a thin long insulator coated conducting wire carrying current I. It is now wound once around an insulating thin disc of radius R to bring the wire back on the same side, as shown in the figure. The magnetic field at the centre of the disc is equal to
Consider a thin long insulator coated conducting wire carrying current I. It is now wound once around an insulating thin disc of radius R to bring the wire back on the same side, as shown in the figure. The magnetic field at the centre of the disc is equal to
Consider a thin long insulator coated conducting wire carrying current I. It is now wound once around an insulating thin disc of radius R to bring th
Physics INK
Problem: Consider a thin long insulator coated conducting wire carrying current I. It is now wound once around an insulating thin disc of radius R to bring the wire back on the same side, as shown in the figure. The magnetic field at the centre of the disc is equal to
(A) `(mu_0I)/(2R)` (B)`(mu_0I)/(4R)[3+2/pi]` (C) `(mu_0I)/(4R)[1+2/pi]` (D)`(mu_0I)/(2R)[1+1/pi]`
Answer:
The magnetic field at the center is
`B=2xxB_("||")+B_O+1/2B_O`
`B=2xx(mu_0I)/(4piR)[sin90^circ+sin0^circ]+3/2(mu_0I)/(2pi)`
`B=(mu_0)/(4R)[3+2/pi]`
Option B is correct.
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